prove that sin^2/cos^2 + cos^2/sin^2 = sec^2 - cosec^2 - 2
Nitinmundhra:
It should be sec2+cosec2-2 in the RHS or
Sin2/cos2 -cos2/sin2 on the LHS
Answers
Answered by
5
Answer:
Step-by-step explanation:I think u need to check the question again regarding the signs
Attachments:
this is wrong
the question is correct
try once again
It could be proved only like this way
Answered by
0
Answer:
Step-by-step explanation:
Note:Your question is actually not right at the RHS because its should be sec^2.cosec^2 - 2 and not sec^2 - Cosec^2 - 2
Now,
Sin^2/Cos^2 + Cos^2/Sin^2
Sin^4 + Cos^4/ (Cos^2)(Sin^2)
(Sin^2 + Cos^2)^2 - 2Sin^2.Cos^2/Cos^2.Sin^2 [Since:(Sin + Cos)^2 =
Sin^2+Cos^2+2SinCos]
(Sin^2 + Cos^2)^2/Cos^2.Sin^2 - 2Sin^2.Cos^2/Cos^2.Sin^2
1/Cos^2.Sin^2 - 2 [Since:Sin^2 + Cos^2 = 1]
Sec^2.Cosec^2 - 2 = RHS Proved
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