Question

Prove that:
sin^2 pi/6 + cos^2 pi/3 - tan^2 pi/4=-1/2​

Answer 1

Answer:

sin π/6 =1/2

cos π/3=1/2

tanπ/4=1

1/4+1/4-1

2/4-1

1/2-1

-1/2

hence proved

Answer 2

Step-by-step explanation:

sin^2π/2 + cos^2π/3 -tan^2 π/4 = -1/2

sin^2 90° + cos^2 60°-tan^45° = -1/2

1/4+ 1/4 -1 = -1/2

2/4-1 = -1/2

1/2-1 = -1/2

-1/2 = -1/2

L.H.S = R.H.S