Question

prove that sin^(2)theta=(a+b)^2/4ab is not possible for any real theta where a,b belongs to real numbers and |a| is not equal to |b|

Answer 1

Step-by-step explanation:

please mark as best answer and thank

Answer 2

$Given, { \sin }^{2} theta = \frac{ {(a + b)}^{2} }{4ab} \\ adding \: - 1 \: on \: both \: sides \: we \: get \\ { \sin}^{2} - 1 = \frac{ {(a + b)}^{2} }{4ab} - 1 \\ { \sin}^{2} - 1 = \frac{ {( {a}^{2} + {b}^{2} + 2ab - 4ab )}}{4ab} \\ { \sin}^{2} - 1 = \frac{ {( {a}^{2} + {b}^{2} - 2ab)}}{4ab} \\ {sin}^{2} - 1 = \frac{ {(a - b)}^{2} }{4ab} \\ hence \: proved$