. Prove that sin 20°. sin 40°. sin 60° sin 80º = 3/16
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sin60°sin40°sin20°sin80°
√3/2[sin40°sin20°]sin80°
2 devid and multiple
√3/4[2sin40°sin20°]sin80°
√3/4[cos20°-cos60°]sin80°
√3/4[cos20°sin80°-1/2sin80°]
√3/8[2cos20°sin80°-sin80°]
√3/8[sin100°-sin(-60°)-sin80°]
√3/8[sin(180°-80°)+√3/2-sin80]
√3/8[sin80°-sin80°+√3/2]
√3/8×√3/2
3/16
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