Math, asked by kanishksingh332, 9 months ago

Prove that sin^24-sin^6=1/2+2√5

Answers

Answered by shahidul07
0

Step-by-step explanation:

Sin18/cos (90 - 18 ) + root 3 ( tan (90 - 80) tan (90 - 50) tan 45 tan50 tan 80)

sin18/sin18 + root 3 ( cot 80 cot 50 tan 45 tan50 tan 80)

1 + root 3(1)

1 + 1 = 2 ANSWER.

note - it should be tan 45 instead of tan 40.

thanks...

OR

______________________________________

Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]

=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]

=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]

=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]

=1 + √3 [tan 30]

=1 + √3 [1/√3]

=1 + 1 = 2

mark as brainliest!!

okay bye....

Similar questions