Prove that sin^24-sin^6=1/2+2√5
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Step-by-step explanation:
Sin18/cos (90 - 18 ) + root 3 ( tan (90 - 80) tan (90 - 50) tan 45 tan50 tan 80)
sin18/sin18 + root 3 ( cot 80 cot 50 tan 45 tan50 tan 80)
1 + root 3(1)
1 + 1 = 2 ANSWER.
note - it should be tan 45 instead of tan 40.
thanks...
OR
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Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]
=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]
=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]
=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]
=1 + √3 [tan 30]
=1 + √3 [1/√3]
=1 + 1 = 2
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okay bye....
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