Question

Prove that sin?24° - sin 60 - (V5-1)​

Answer 1

Let us consider the LHS sin2 24° – sin2 6° As we know, sin (A + B) sin (A – B) = sin2A – sin2B Now the above equation becomes, sin2 24° – sin2 6° = sin (24° + 6°) – sin (24° – 6°) = sin 30° – sin 18° = sin 30° – (√5 – 1)/4 [since, sin 18° = (√5 – 1)/4] = 1/2 × (√5 – 1)/4 = (√5 – 1)/8 = RHS Thus proved.

                          other method

We have, sin²A-sin²B=sin(A+B)sin(A-B) hence, sin²24-sin²6=sin30sin18=(1/2)(√5-1)/4=(√5-1)/8 Answer: (√5-1)/8

Answer 2

Answer:

See the answer

Step-by-step explanation:

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