Question

prove that sin 2A = 2 sin A when A = 0 degree​

Answer 1

SOLUTION

TO PROVE

sin 2A = 2 sin A when A = 0°

EVALUATION

Here it is given that A = 0°

Now we have to prove that

sin 2A = 2 sin A

LHS

= sin 2A

= sin ( 2 × 0° )

= sin 0°

= 0

RHS

= 2 sin A

= 2 sin 0°

= 2 × 0

= 0

∴ LHS = RHS

Hence proved

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Answer 2

HELLO DEAR,

GIVEN:- Sin2A = 2 SinA , when A = 0°

TO PROVE - Sin2A = 2 SinA, when A = 0°.

SOLUTION:- Taking LHS,

Sin2A , where A = 0°

Sin(2×0°) = Sin0°

= 0

Taking RHS,

2 SinA , where A =0°

2 Sin0° = 2× 0

= 0.

So, LHS = RHS

Hence, proved that Sin2A = 2 SinA.

THANKS.