Question

PROVE THAT
Sin^2A×Cos^2B-Cos^2A×Sin^2B=Sin^2A-Cos^2B

Answer 1

Answer:

Step-by-step explanation:

How can I prove sin^2A*cos^2B- cos^2Asin^2B = sin^2A-sin^2B?

LHS = sin^2A*cos^2B- cos^2Asin^2B

= sin^2A*(1-sin^2B)- (1-sin^2A)*sin^2B

= sin^2A -sin^2A*sin^2B -sin^2B+sin^2A*sin^2B

= sin^2A -sin^2B = RHS.

Proved.