Prove that sinθ -2sin^3θ/2 cos^3 -cosθ = tanθ
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(sin@-2sin³@)/(2cos³@-cos@),
[sin@(1-2sin²@)]/[cos@(2cos²@-1)],
(sin@×cos2@)/(cos@×cos2@),
sin@/cos@,
tan@
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