Prove that ( sinθ - 2sin^3θ) = (2 cos^3θ - cosθ) tanθ
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as tan0 is sin upon cos
so ( sinθ - 2sin^3θ) = (2 cos^3θ)
now 2sin3 0 is 1/2cos
so ( sinθ - 2sin^3θ) = (2 cos^3θ)
now 2sin3 0 is 1/2cos
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Hello mate
your question is wrong
In the place of equals to u have to put divide sign
your question is wrong
In the place of equals to u have to put divide sign
Ritikagupta12:
No, question is correct
nope
u can check
if u know then answer plz
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