Question

Prove that ( sinθ - 2sin^3θ) = (2 cos^3θ - cosθ) tanθ

Answer 1

as tan0 is sin upon cos
so ( sinθ - 2sin^3θ) = (2 cos^3θ)
now 2sin3 0 is 1/2cos

Answer 2

Hello mate

your question is wrong

In the place of equals to u have to put divide sign