prove that sin^2theta+cos^2theta=1
Answers
Answered by
10
hey mate!
here is your answer:
sin theta=perpendicular/hypotenuse
cose theta=base/hypotenuse
sin^2theta+cos^2theta=(perpendicular/hypotenuse)^2+(base/hypotenuse)^2 =perpendicular^2/hypotenuse ^2+base^2/hypotenuse ^2
=perpendicular ^2+base^2/hypotenuse ^2
=hypotenuse ^2/hypotenuse ^2(by pythagorus theorem)
=1
hope it helped!
here is your answer:
sin theta=perpendicular/hypotenuse
cose theta=base/hypotenuse
sin^2theta+cos^2theta=(perpendicular/hypotenuse)^2+(base/hypotenuse)^2 =perpendicular^2/hypotenuse ^2+base^2/hypotenuse ^2
=perpendicular ^2+base^2/hypotenuse ^2
=hypotenuse ^2/hypotenuse ^2(by pythagorus theorem)
=1
hope it helped!
Answered by
20
✌✌hey here is ur ans ...✌✌
hope it will help uh ..
nd plz mark as brainliest ..☺☺
hope it will help uh ..
nd plz mark as brainliest ..☺☺
Attachments:
dishagaur748:
hey mate at last you have written sin^2+cos^2=1 but that is the only thing we need to prove so, how did you prove it??
now fine ,good answer friend
Similar questions