Question

prove that,sin (π/3-x)×cos(π/6+x)+cos(π/3-x)×sin(π/6+x)=1​

Answer 1

Answer:

1

Step-by-step explanation:

sin (π/3-x)×cos(π/6+x)+cos(π/3-x)×sin(π/6+x)

= 1/2{ 2sin (π/3-x)×cos(π/6+x)+ 2cos(π/3-x)×sin(π/6+x)}

= 1/2{ sinπ/2 + sin(π/6-2x ) + sin(π/2) - sin(π/6-2x )}

= 2sinπ/2 ÷2

= sinπ/2

=1