Question

Prove that sin 37° * sec 52° =1

Answer 1

Step-by-step explanation:

$\sin(37) \times \sec(53) \\ = \sin(37) \times cosec(90 - 53) \\ \ = sin(37) \times cosec(37) = 1$

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$\sin(38) \times \sec(52) \\ = \sin(38) \times cosec(38) = 1$

Answer 2

Answer:

}

sin(37)×sec(53)

=sin(37)×cosec(90−53)

=sin(37)×cosec(37)=1

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\begin{gathered} \sin(38) \times \sec(52) \\ = \sin(38) \times cosec(38) = 1\end{gathered}

sin(38)×sec(52)

=sin(38)×cosec(38)=1