Prove that:-. {Sin^3A+cos^3A/sinA+cosA}+ sinA.cosA=1
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this is the proof for your question
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Step-by-step explanation:
(sin ^3 A + cos^3 A)/(sinA + cosA)
or (sin ^2 A *sinA + cos^2 A*cosA)/(sinA + cosA)
or ((1-cos^2 A)*sinA + (1-sin^2 A)*cosA)/(sinA + cosA)
or (sinA-cos^2 AsinA + cosA-sin^2 AcosA)/(sinA + cosA)
or (sinA + cosA - cos^2 AsinA - sin^2 AcosA)/(sinA + cosA)
or (sinA + cosA - cos^2 AsinA - cosAsin^2 A)/(sinA + cosA)
or ((sinA + cosA) - cosAsinA*(cosA + sinA))/(sinA + cosA)
or ((sinA + cosA) - cosAsinA*(sinA + cosA))/(sinA + cosA)
or ((sinA + cosA)*(1 - cosAsinA))/(sinA + cosA)
or (sinA + cosA)*(1 - cosAsinA)/(sinA + cosA)
or (1 - cosAsinA) (cancelling common numerator and denominator)
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