prove that sin 3A / sin A - cos 3A / cosA = 2
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Step-by-step explanation:
sin(3a) / sin(a) - cos(3a) / cos(a)
= [sin(3a) cos(a) - cos(3a) sin(a)] / sin(a) cos(a)
= sin(3a - a) / [1/2 sin(2a)]
= 2
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