Question

prove that sin^3o+cos^3o/sino+coso=1-sino.coso​

Answer 1

Answer:

sin^30=1/4

cos^30=3/4

1=sim^o+cos^o

sin^3o+cos^3o/sino+coso=1/4+34/sino+coso

1/sino+coso=(sino+coso)^/sino+coso