Question

Prove that
sin^4 A cosec^2 A + cos^4 A sec^2 A = 1
​

Answer 1

Step-by-step explanation:

hope this would help

1st convery cosec into sin and sec into cos so that inverse will get cancelled then sin² and cos² will n remaining whose sum is equal to 1

Answer 2

Answer:

sin^4 A cosec^2 A + cos^4 A sec^2 A = 1 [True]

Step-by-step explanation:

${ \sin(x) }^{4} \times { \csc(x) }^{2} + { \cos(x) }^{4} \times { \sec(x) }^{2} \\ { \sin(x) }^{4} \times ({ \frac{1}{ \sin(x) }})^{2} + { \cos(x) }^{4} \times ({ \frac{1}{ \cos(x) } )}^{2} \\ { \sin(x) }^{2} + { \cos(x) }^{2} = 1$