Question

prove that sin(40+ θ).cos(10+ θ)-cos(40+ θ).sin(10+ θ)=1/2

Answer 1

Step-by-step explanation:

as we know that:

sin(A-B)= sinA×cosB - cosA×sinB

here

A=40+Q , B= 10+Q

so,

it become

sin( 40+Q-10-Q)

=sin30

=1/2