prove that sin 45 = cos 45
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sin(45+A).cos(45-B)+cos(45+A).sin(45-B)=cos(A-B).
L.H.S.
Let (45+A) =x ,and (45-B) = y.
= sin x.cos y+cos x.sin y
= sin ( x+y) , on putting the values of x and y.
= sin(45+A+45-B)
= sin{ 90 +(A-B) }
= cos ( A - B ) , proved.
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