Math, asked by sweetysunita67, 6 months ago

prove that : sin (45°+A) +cos (45+A) = √2 cosA

Answers

Answered by sharma41abhay

3

Proof : -

L.H.S. = sin(45° + A) + cos(45°+ A)

= sin45° cosA + cos45° sinA + cos45°cosA - sin45°sinA

= 1/√2 cosA + 1/√2 sinA + 1/√2 cosA - 1/√2 sinA

= 1/√2cosA + 1/√2cosA

= √2 cosA = R.H.S.

PLEAASE MARK IT AS BRAINLIEST

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