Question

prove that sin (45°+A) - cos(45°-A) = 0​

Answer 1

Answer:

Step-by-step explanation:

sin (45°+A ) - sin ( 45° - A )

= sin ( 90°-(45°+A)) + sin ( 45° - A )

= sin ( 45° - A ) - sin ( 45° - A )

=. 0

Hence, proved

Answer 2

Step-by-step explanation:

we know that

cos x = sin (90-x)

$sin \: (45 + a) - \cos(45 - a) = \\ sin((45 + a) -cos(90-(45- a))$

$= \sin(45 + a) - \sin(45 + a) \\ = 0$