Prove that
Sin 48 sec 420 et
cos 48° . cosec 42 = 2
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The value of
sin 48 sec 42 + cos 48 cosec 42
= sin(90 – 42) sec42 +cos(90 – 42)cosec42
= cos 42 sec 42 + sin42 cosec 42
=cos42 x 1/cos 42 + sin 42×1/cos 42
= 1+1
Therefore,
The value of sin48 sec42 + cos48 cosec42
= 2
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