Prove that sin^4A-cos^4A =2sin^2A-1
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RHS= 2sin^2a + cos ^ 4a
= 2sin^2a + (cos^2a)^2
= 2sin^2a + (1-sin^2a)^2
= 2sin^2a +1 -2sin^2a+sin^4a
= 1 + sin^4a
= LHS
LHS = RHS
HENCE PROVED
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