Prove that :sin^4A - cos^4A = sin^2A - cos^2A
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from here we get
(sin^2A+cos^2A)(Sin^2A-cos^2A)
as a^2-B^2=a+b*a-b
so take Sin^2A as a
(sin^2A+cos^2A)(Sin^2A-cos^2A)
as a^2-B^2=a+b*a-b
so take Sin^2A as a
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