Math, asked by chjangaiahchjangaiah, 9 months ago

prove that sin^4A+sin^2A*cos^2A-sin^2A=0

Kaimaster1: Test

Kaimaster1: test

Answers

Answered by steevejoy123

1

Answer:

Step-by-step explanation:

sin^2A = sin^4A + sin^2A*cos^2A

= sin^4A + sin^2A(1 - sin^2A)

= sin^4A + sin^2A - sin^4A

= sin^2A

:- **sin^4A + sin^2A*cos^2A - sin^2A = 0**

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