prove that sin^4A+sin^2A*cos^2A-sin^2A=0
Kaimaster1:
Test
Answers
Answered by
1
Answer:
Step-by-step explanation:
sin^2A = sin^4A + sin^2A*cos^2A
= sin^4A + sin^2A(1 - sin^2A)
= sin^4A + sin^2A - sin^4A
= sin^2A
:- sin^4A + sin^2A*cos^2A - sin^2A = 0
Similar questions