Question

prove that -sin(50+ θ)×COS (20+θ) – Cos(50+θ) ×Sin (20+θ) =1/2​​

Answer 1

Answer:

Step-by-step explanation:

Sin(A-B) = SinACosB - CosASinB

Sin(50+ θ)×Cos(20+θ) – Cos(50+θ)Sin (20+θ)

=> Sin(50+ θ - 20 -θ)

=> Sin30°

=> 1/2

= R.H.S

Hence proved.