prove that -sin(50+ θ)×COS (20+θ) – Cos(50+θ) ×Sin (20+θ) =1/2
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Answer:
Bro, your question has a mistake. If there is a - sign in the sin(50 + θ) the answer cannot be proved. It has to be like this:
sin(50 + θ)cos(20 + θ) - cos(50 + θ)sin(20 + θ)
Step-by-step explanation:
LHS = sin(50 + θ)cos(20 + θ) - cos(50 + θ)sin(20 + θ)
= sin(50 + θ)cos(20 + θ) - cos(50 + θ)sin(20 + θ))
= sin( 50 + θ - 20 - θ))
= sin (30)
= 1/2 = RHS
Hence proved
MARK AS BRAINLIEST :)
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