Question

Prove that:sin(50°+theta)-cos(40°-theta)=0​

Answer 1

$\huge \bold \red{hello \: mate}$

sin(50+theta)- cos (40-theta)

= sin(90-40+theta) - cos(40-theta)

=sin[90-(40-theta)]- cos(40-theta)

=cos(40-theta)-cos(40-theta) since sin(90-theta)=cos theta

=0

☺️BRAINLIEST PLS☺️

Answer 2

Answer:

cos (90- 50)=sin 50.is your right answer

Barinliest plus