Prove that sin 56°-sin 44°/cos 56°+cos 44° = cot 82°
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Answer:
proved
Step-by-step explanation:
LHS = sin 56°-sin 44°/cos 56°+cos 44° = 2 cos 50° sin 6°/2 cos 50° cos 6°
= sin 6° / cos 6° = tan 6° = cot 84° = RHS
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