Question

prove that sin(60+A)-sin(60-A) = sin A (please explain correctly)​

Answer 1

Solution:-

$\implies \red {LHS} \\ \implies \: \sin(60 -A ) - \sin(60 -A )$

$\implies \: \sin60. \cos \: A + \cos 60\: . \sin \: A - ( \sin60. \cos \: A - \cos60 \: . \sin \: A) \\ \\ \implies \: \sin60. \cos \: A + \cos 60\: . \sin \: A - \sin60. \cos \: A + \cos60 \: . \sin \: A) \\ \\ \implies \: 2 \: \cos60. \sin \: A \\ \\ \implies \cancel{ 2} \times \frac{1}{ \cancel{2}} \: \: . \sin \: A \\ \\ \implies \: \sin \: A \red{(hence \: proved)}$

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