prove that sin 70°/cos 20°+ cosec 20°/sec 70°- 2cos 70° * cosec 20°=0
Answers
Answered by
8
Answer:
0
Step-by-step explanation:
sin(90-20)°/cos20° + cosec(90-70)°/sec70° - 2cos(90-20)° cosec20°
= cos20°/cos20° + sec70°/sec70° - 2 sin20° cosec 20°
1 + 1 - 2× 1/cosec20° * cosec20°
= 1+ 1 - 2 = 0
hence proved
Similar questions