prove that
sin 70° - cos 40°/
cos 50° -sin 20°=
1/root 3
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Answer:
we know that tan 0-cot 0÷1
cot 80.tan 80=1
cot 70.tan 70=1
sin 40+sin50+tan 60
we know that:sin=cos +(90-0)
sin 40=cos (90-40)=cos 50
cos 50 + sin 50 +sin50+tan 60
=1+tan 60
since sin 50+cos 50+tan 60
we know that tan 60 √3
1+√3
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