Question

prove that sin 8 theta cos theta - sin 6 theta cos 3 theta /cos 2 thetha cos thetha - cos 3 thetha cos 4 thetha = 5 cot thetha​

Answer 1

Answer:

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

Using Pythagoras theorem:-

(3)²+(4)²=(5)²

9+16=25

so hypotenuse=5

sin theta=perpendicular/hypotenuse

=3/5

cos theta=base/hypotenuse

=4/5

HOPE IT HELPS YOU:-))

Answer 2

$\huge{\underline{\red{\mathcal{AnsWer}}}}$

Using Pythagoras theorem:-

(3)²+(4)²=(5)²

9+16=25

so hypotenuse=5

sin theta=perpendicular/hypotenuse

=3/5

cos theta=base/hypotenuse

=4/5

$\huge{\boxed{\mathbb\pink{\fcolorbox{red}{purple}{Thanks}}}}$