Question

prove that sin(90-a)/cosec(90-a) + cos(90-a)/sec(90-a)=1

Answer 1

Answer:

please refer the attachment for procedure

Answer 2

Step-by-step explanation:

= sin(a)/cosec(a) + cos(a)/sec(a)

= sin(a)/1/sin(a) + cos(a)/1/cos(a)

( Since, cosec(ø) = 1/sin(ø) &

sec(ø) = 1/cos(ø) )

= sin^2(a) + cos^2(a)

( W.K.T., sin^2(Ø) + cos^2(Ø) = 1 )

Therefore,

sin^2(a) + cos^2(a) = 1

Hence proved...

(P.S. - Please mark as Brainliest if you are satisfied with my answer.)