Question

prove that sin ( 90 - cheta) / 1 + sin cheta + cos cheta/ 1 - cos ( 90 - cheta) = 2 sec cheta​

Answer 1

Answer:

LHS = cosθsin(90°−θ)+sinθcos(90°−θ)

⇒LHS=cosθcosθsinθsinθ

⇒LHS=cos 2 θ+sin 2 θ=1 = RHS

Answer 2

Step-by-step explanation:

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