Question

Prove that
sin (90° - A) cos (90° - A)=tan A/1+tan2 A​

Answer 1

ANSWER:

HI,

MY DEAR FRIEND

LHS=SIN(90_A)×COS(90_A)

=COSA ×SIN ----------- (1)

TANA/SEC²A

=(SINA/COSA)/(1/COS²A)

=SINA × COSA

SINA×COSA-------------(2)

LHS=RHS

Answer 2

ANSWER:

HI,

MY DEAR FRIEND

LHS=SIN(90_A)×COS(90_A)

=COSA ×SIN ----------- (1)

TANA/SEC²A

=(SINA/COSA)/(1/COS²A)

=SINA × COSA

SINA×COSA-------------(2)

LHS=RHS