Question

Prove that:
sin(90°-θ)cos(90°-θ)=tanθ/1+tan²θ
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Answer 1

Step-by-step explanation:

hey dear here is ur ans:)

LHS = sin(90°-theta) × cos(90°- theta)

= cos theta × sin theta

= sin theta × cos theta

RHS = tan theta / 1 + tan^2 theta

= tan theta / sec^2 theta

= (sin theta / cos theta) × cos^2 theta

= sin theta × cos theta

Hence, LHS = RHS

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Answer 2

Answer:

the answer is in hand written form

Step-by-step explanation:

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