Question

prove that sin a-2 sin queb a upon 2 cos queb a-cos a=tan a​

Answer 1

Answer:

tanA

Step-by-step explanation:

(sinA - 2.sin^3A)/(2cos^3A-cosA)= tanA.

L.H.S.

=sinA(1–2.sin^2A)/cosA(2cos^2A-1)

=sinA.(1–2.sin^2A)/cosA{2(1-sin^2A)-1}

=sinA(1–2sin^2A)/cosA.(2–2sin^2A-1)

=sinA.(1–2sin^2A)/cosA.(1–2sin^2A)

= sinA/cosA

=tanA. Proved.

Answer 2

Answer:

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Step-by-step explanation:

refers to the attachment ✌❣

hope it will help you little bit