Question

prove that sin (A-B) /sin(A+B) = a^2-b^2/c^2 ​

Answer 1

Answer:

proved

Step-by-step explanation:

sin(A-B)/sin(A+B)

= sinA cosB - sinB cosA/sinA cosB + sinA cosB

= 2ac cosB - 2bc cosA/ 2ac cosB + 2bc cosA

= (a²-b²+c²)-(-a²+ b²+ c²)/(a²-b²+c²)+(-a²+ b²+c²)

= a²-b²/c²

hence, proved

Answer 2

Answer:

$sin (A-B) /sin(A+B) = a^2-b^2/c^2 \: proved.$

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