Math, asked by amaljyothi79, 1 month ago

prove that Sin(A+B)+Sin(A-B)=Cos^2B-Cos^2A

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Answered by anushkaranade04

L.H.S = sin(A + B) sin(A – B) = (sinA cosB + cosA sinB) (sin A cosB – CosA sinB) = sin2A cos2B – cos2A sin2B = (1 – Cos2A) cos2B – cos2A (1 – cos2B)-cos-2a

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prove that Sin(A+B)+Sin(A-B)=Cos^2B-Cos^2A​

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prove that Sin(A+B)+Sin(A-B)=Cos^2B-Cos^2A