Prove that, sin(A + B) sin(A - B) = sin A sin B.
Answers
Answered by
0
Answer:
ANSWER
Assuming ∠A=60
∘
and ∠B=30
∘
L.H.S=sin(A+B)=sin(60
∘
+30
∘
)
=sin(90
∘
)=1
R.H.S=sinA+sinB=sin60
∘
+sin30
∘
=
2
3
+
2
1
=
2
3
+1
Thus, L.H.S
=R.H.S
Thus,sin(A+B)
=sinA+sinB
Answered by
0
Answer:
ANSWER
Assuming ∠A=60
∘
and ∠B=30
∘
L.H.S=sin(A+B)=sin(60
∘
+30
∘
)
=sin(90
∘
)=1
R.H.S=sinA+sinB=sin60
∘
+sin30
∘
=
2
3
+
2
1
=
2
3
+1
Thus, L.H.S
=R.H.S
Thus,sin(A+B)
=sinA+sinB
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