prove that
sin(A+B)/sin(A-B)
= TanA +Tan B / Tan A - Tan B
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Anonymous:
kisne kiya
Answered by
18
Let's take
RHS
= tan A + tan B tan A - tan B
=sin Acos A + sin Bcos Bsin Acos A - sin Bcos B
=sin A . cos B + cos A . sin Bsin A . cos B - cos A . sin B
=sinA+BsinA-B
=LHS
RHS
= tan A + tan B tan A - tan B
=sin Acos A + sin Bcos Bsin Acos A - sin Bcos B
=sin A . cos B + cos A . sin Bsin A . cos B - cos A . sin B
=sinA+BsinA-B
=LHS
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