Math, asked by abhishek450, 1 year ago

prove that sin(A-B)= sinA.cosB-cosA.sinB

Answers

Answered by 123jayavardhan123
4
this might be helpful
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Answered by Shaizakincsem
4

Thank you for asking this question. Here is your answer:


Sin ( A - B) = O/H = ST/1 = ST


ST = PR - PQ


QR = ST


Sin (B) = O/H = PS/1 = PS


Cos (B) = A/H = OP/1 = OP


Sin (A) = O/H = PR / Cos(B)


Sin (A) cos(B) = PR


cos(A) = A/H = PQ/Sin (B)


Cos(A) sin(B) = PQ


ST = PR - PQ


Sin (A-B)


= sin(A) cos(B) - cos(A) sin (B)


If there is any confusion please leave a comment below.

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