Question

prove that sin(A +B) = SinACOS B+COSA SinB​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge\underline \mathfrak \red{Answer}$.

Here, is a proof without using complex numbers from Apostol.

Here is a proof without using complex numbers, from Apostol.

sin(A+B)

=−cos(A+B+π/2)

=−cosAcos(B+π/2)+sin(A) sin(B+π/2)

sin(A+B)

=−cos(A+B+π/2)

=−cosAcos(B+π/2)+sin(A) sin(B+π/2)

=SinACos B+CosA SinB

Assuming you can prove the formula for the cosine, of course, which Apostol gives as a property of the cosine.

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