Prove that (sin A - cos A)(cos A - sec A)(tan A + cot A) = 1
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Answer:
Step-by-step explanation;
Given:
( secA + tanA ) ( 1 - sinA )
we know that
secA = 1/cosA
tanA = sins/cosA
now
( 1 /cosA + sinA /cosA ) ( 1 - sinA )
= ( 1 + sinA ) ( 1 - sinA )/ cosA
= 1² - sin²A / cosA
= cos²A / cosA
= cosA
RHS
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Answered by
1
Given
( secA + tanA ) ( 1 - sinA )
we know that
secA = 1/cosA
tanA = sins/cosA
now
( 1 /cosA + sinA /cosA ) ( 1 - sinA )
= ( 1 + sinA ) ( 1 - sinA )/ cosA
= 1² - sin²A / cosA
= cos²A / cosA
= cosA
RHS
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