Question

prove that (sin A + cos A)(cot A + tan A) = sec A + cosec A
5.
Ans.​

Answer 1

(sinA - cosA)(cotA + tanA)=secA - cosecA

lhs → (sinA - cosA)[(cosA/sinA) + (sinA/cosA)]

=(sinA - cosA)(cos²A + sin²A/sinAcosA)

=(sinA - cosA)(1)/sinAcosA

=(sinA - cosA)/sinAcosA

=1/cosA - 1/sinA

=secA - cosecA

rhs → secA - cosecA

lhs=rhs

hence proved

Answer 2

Answer:

Step-by-step explanation:

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