Question

prove that (sin a +cos a)(tan a +cot a = sec a + cosec a​

Answer 1

$\bf\large\underline\pink{Answer:-}$

(sinA - cosA)(cotA + tanA)=secA - cosecA

lhs → (sinA - cosA)[(cosA/sinA) + (sinA/cosA)]

=(sinA - cosA)(cos²A + sin²A/sinAcosA)

=(sinA - cosA)(1)/sinAcosA

=(sinA - cosA)/sinAcosA

=1/cosA - 1/sinA

=secA - cosecA

rhs → secA - cosecA

lhs=rhs

hence proved

Answer 2

HEY MATE THIS IS THE ANSWER IN THE ATTACHMENT