Question

prove that Sin A + Cos A whole square + Sin A minus Cos A whole square is equal to 2​

Answer 1

Answer:

1. (sinA+cosA) square +(sinA- cos A) asqure =2
2. (sinA+ cosA)square-(sinA + cosA)square= 2...............(+)(-)=(-)
3. than(sinA+cosA)square and (sonA+cosA)square is cancle .......because(2) no.equation
4. that is = 2

Answer 2

Consider the provided information.

\sin^2A\cos^2B-\cos^2A\sin^2B=\sin^2A-\sin^2B

Consider the LHS.

\sin^2A\cos^2B-\cos^2A\sin^2B

\sin^2A(1-\sin^2B)-(1-\sin^2A)\sin^2B               (∴\cos^2x=1-\sin^2x)

\sin^2A-\sin^2A\sin^2B-\sin^2B+\sin^2A\sin^2B

\sin^2A-\sin^2B

Hence, proved.