Question

Prove that:- sin A - cosA +1/
sin A + cosA-1=
1/sec A-tan A​

Answer 1

Answer:

solve LHS and RHS separately. Divide each term of LHS by cosA

Step-by-step explanation:

for details find the attatched file

Answer 2

Step-by-step explanation:

L.H.S= SinA- CosA+1/SinA+CosA-1

= tanA-secA/tanA+1-secA

=(tanA-secA)-1/(tanA-secA)+1

= {(tanA+secA)-1}(tanA-secA)/{(tanA-secA)+1}(tanA-secA)

=(tan^2A-sec^2A)-(tanA-sec^2A)/{tanA-secA+1}(tanA-secA)

=-1-tanA+secA/(tanA-secA+1)(tanA- secA)

=-1/tanA-secA

= 1/secA-tanA

=R.H.S.

Hence proved