Question

prove that
sin A-cosA+1/sinA+cosA-1=1/secA-cosA​

Answer 1

Answer:

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Step-by-step explanation:

LHS = sinA-cosA+1/sinA+cosA-1

divide both numerator and denominator by cosA

LHS=(tanA−1+secA)/(tanA+1−secA)  

Now

sec2A=1+tan2A  

sec2A−tan2A=1  

Using above relation at denominator of LHS

LHS=(tanA−1+secA)/(tanA−secA+sec2A−tan2A)  

LHS=(tanA−1+secA)/((secA−tanA)(−1+secA+tanA))  

LHS=1/(secA−tanA)  

LHS=RHS  

Hence Proved.